What is the 14th term for the geometric sequence 8, - 16, 32, - 64,

Here we go

an=a1 (r^ (n-1))

a1=first term

r=common ratio

n=which term

common ratio is - 2 (8 times - 2=-16, - 16*-2=32)

first term is 8

n is 14

a14=8 * (-2) ^ (14-1)

a14=8 * (2) ^13

a14=8 * (-8192)

a14=-65536

The 14th term would be - 224