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1 October, 23:27

What is a quartic function with only the two real zeros given?

x = - 4 and x = - 1

A. y = x^4 + 5x^3 + 5x^2 + 5x + 4

B. y = x^4 - 5x^3 - 5x^2 - 5x - 4

C. y = - x^4 + 5x^3 + 5x^2 + 5x + 4

D. y = x^4 + 5x^3 + 5x^2 + 5x - 5

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  1. 1 October, 23:49
    0
    A x+4=0 x+1=0 so factores (x+4) (x+1) = 0; x^2+5x+4 is a factor. Divide it into x^4+5x^3+5x^2+4 and you get x^2+1 as the other factor which would be your other 2 roots (imaginary)
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