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8 June, 03:39

A biased die has a probability of 1/4 of showing a 5, while the probability of any of 1, 2, 3, 4, or 6 turning up is the same. If three such dice are rolled, what is the probability of getting a sum of at least 14 without getting a 6 on any die?

Option 1 : 5/24

Option 2 : 9/160

Option 3 : 1/30

Option 4 : 7/160

+5
Answers (1)
  1. 8 June, 03:59
    0
    Possibilities of outcomes:

    5, 5, 5

    5, 5, 4

    P (sum at least 14) = P (5,5,4) + P (5,5,5)

    = 1/4 x 1/4 x 3/20 + 1/4 x 1/4 x 1/4

    1/40
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