What is the sum of a 6-term geometric sequined if the first term is 22 and the last term is 1299078

1461460

Step-by-step explanation:

From the question given, we obtained the following dа ta:

a = 22

Last term = T6 = 1299078

Let us find the common ratio (r)

Tn = ar^ (n-1)

T6 = ar^5

1299078 = 22r^5

Divide both side by 22

r^5 = 1299078/22

r^5 = 59049

Take the fifth root of both side

r = 5√ 59049

r = 9

Now we can find the sum of the 6th term as follows

Sn = a[ (r^n) - 1] / (r - 1)

S6 = 22[ (9^6) - 1] / 9-1

S6 = 22[ (9^6) - 1] / 9-1

S6 = 22[531441 - 1] / 8

S6 = 22[531440] / 8

S6 = 22 x 66430

S6 = 1461460