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9 July, 20:22

Counting numbers are to be formed using only the digits 9, 3, 5, 8, 7, 6, 4, and 1. Determine the number of different possibilities for two-digit numbers.

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  1. 9 July, 20:32
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    64.

    Step-by-step explanation:

    There are 8 digits in the list.

    This will be the number of permutations of 2 from 8 plus the duplicate numbers 11, 22 etc.

    So we have 8P2 + 8 possibilities.

    = 8! / (8-2) ! + 8

    = 56 + 8

    = 64.
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