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23 December, 12:51

If AB=2 (x+1) BC=3x+1 and AC=4 (x+2) then find the value for x, AB, BC and AC

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Answers (1)
  1. 23 December, 13:04
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    Givens

    AB + BC = AC

    AB = 2 (x + 1)

    BC = 3x + 1

    AC = 4 (x + 2)

    Substitute and Solve

    AB + BC = AC

    2 (x + 1) + 3x + 1 = 4 (x + 2) Remove the brackets on the left

    2x + 2 + 3x + 1 = 4 (x + 2) Collect the like terms on the left

    5x + 3 = 4 (x + 2) Remove the brackets on the right.

    5x + 3 = 4x + 8 Subtract 4x from both sides.

    5x - 4x + 3 = 8

    x + 3 = 8 Subtract 3 from both sides

    x = 8 - 3

    x = 5

    Answers

    AB=2 (5 + 1) = 2 * 6 = 12

    BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16

    AC = 4 (5 + 2) = 4*7 = 28
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