Four friends were born in consecutive years. The sum of their ages is 94. What is the age of the oldest friend?

Hello,

We don't need algebra to solve this.

I suppose the ages are 1,2,3,4

Their sum is 1+2+3+4=10.

To obtain 94 we must add 94-10=84 for 4 persons = >84/4=21 to each

Ages are

1+21=22

2+21=23

3+21=24

4+21=25

But if really want an algebric resolution:

Let's x the age of the youngest

x+1, x+2, x+3 the others.

x + (x+1) + (x+2) + (x+3) = 94

==>4x+6=94

==>4x=88

==>x=22

Ages are 22,23,24,25.

The oldest friend is 25 years old.