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12 November, 06:00

One positive number is the square of another positive number. their sum is 132. find the numbers.

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  1. 12 November, 06:07
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    X + x² = 132

    x + x²-132 = 132-132

    x²+x - 132 = 0

    (x-11) (x+12) = 0

    x-11 = 0 X+12=0

    x-11+11 = 0+11 X+12-12=0-12

    x = 11 x = - 12

    Check

    x + x² = 132 x + x² = 132

    -12 + - 12² = 132 11 + 11² = 132

    -12 + 144 = 132 11 + 121=132

    132 = 132 132=132

    Since the problem says positive the answer is (11,121)
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