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26 August, 19:54

Calculate the work associated with the expansion of a gas

from46l to64 l at

a constant external pressure of 15 atm?

+1
Answers (1)
  1. 26 August, 21:43
    0
    -27 kJ

    Step-by-step explanation:

    Given data

    Initial volume (Vi) : 46 L Final volume (Vf) : 64 L External pressure (P) : 15 atm

    We can find the work (w) associated with the expansion of a gas using the following expression.

    w = - P. ΔV

    w = - P. (Vf - Vi)

    w = - 15 atm. (64 L - 46 L)

    w = - 270 atm. L. (101.325 J / 1 atm. L)

    w = - 2.7 * 10⁴ J

    w = - 27 kJ
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