Ask Question
5 August, 08:18

With her motorboat at full speed Dawn gets to her fishing hole, which is 21 miles upstream, in 2 hours. The return trip takes 1.5 hours. How fast could her motorboat go in still water? What is the rate of the current?

+2
Answers (1)
  1. 5 August, 08:20
    0
    Speed_still = 12.25 mi/h

    Speed_current = 1.75 mi/h

    Step-by-step explanation:

    In the first trip, the motorboat goes upstream

    Speed_boat = Speed_still - Speed_stream

    The speed is defined as

    Speed = Distance / time

    This means

    Speed_boat = 21 miles / 2 h = 10.5 mi/h

    Then

    Speed_still - Speed_stream = 10.5 mi/h

    In the second trip:

    Speed_boat = Speed_still + Speed_stream

    Speed_boat = 21 miles / 1.5 h = 14 mi/h

    Speed_still + Speed_stream = 14 mi/h

    Then, the ystem of equations result

    Speed_still + Speed_stream = 14 mi/h

    Speed_still - Speed_stream = 10.5 mi/h

    If we add them together

    2*Speed_still = 24.5 mi/h

    Speed_still = 12.25 mi/h

    Speed_stream = 14 mi/h - 12.25 mi / h = 1.75 mi/h
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “With her motorboat at full speed Dawn gets to her fishing hole, which is 21 miles upstream, in 2 hours. The return trip takes 1.5 hours. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers