Find the zeros of the function.

f (x) = 9x^3 + 18 x^2 - 135x

Where f (x) = 0 is the zeros of the funciton

factor out the common factor of all of them which is 9x

f (x) = 9x (x^2+2x-15)

what 2 numbers multiply to get - 15 and add to get 2?

5 adn - 3

f (x) = (9x) (x+5) (x-3)

set to zero

9x=0

x=0

x+5=0

x=-5

x-3=0

x=3

zeroes at x=-5, 0,3