Ask Question
11 February, 13:13

There are 4 consecutive integers that have a sum of 58. what is the least of these integers?

+4
Answers (1)
  1. 11 February, 13:19
    0
    Easy way

    58:4 = 14.5 is center of the integers

    13 is the least of these integers

    14

    15

    16

    Equations:

    4 consecutive numbers

    X, X+1, X+2, X+3

    13, 14, ... 15 ... 16

    X + X+1 + X+2 + X+3 = 58

    4X + 6 = 58

    4X = 58-6 = 52

    X = 52/4 = 13
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “There are 4 consecutive integers that have a sum of 58. what is the least of these integers? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers