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Dud
Mathematics
18 February, 11:18
Solve by factoring: x^4-12x^2 = 64
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Davion Cole
18 February, 11:25
0
Minus 64 from both sides
x⁴-12x²-64=0
hmm
what 2 numbers multiply to - 64 and add to get - 12
-16 and 4
(x²-16) (x²+4) = 0
oh look a difference of 2 perfect squares
(x²-4²) (x²+4) = 0
(x-4) (x+4) (x²+4) = 0
set each to zero
x-4=0
x=4
x+4=0
x=-4
x²+4=0
x²=-4
if you have learend complex roots then
sqrt both sides to get
x=-2i or 2i
solutions are
x=-4, 4, 2i or - 2i
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Alena Maldonado
18 February, 11:43
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The final solution is all the values that make (x+4) (x - 4) (x2 + 4) = 0 x+4 x - 4 x2 + 4 = 0 true. x = - 4,4, 2i, - 2 i
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