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21 May, 00:26

In ΔLMN, m = 5.9 cm, n = 8.7 cm and ∠L=163°. Find the length of l, to the nearest 10th of a centimeter.

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Answers (2)
  1. 21 May, 00:37
    0
    its 14.4
  2. 21 May, 00:52
    0
    Answer: side l = 14.5 centimeters (approximately)

    Step-by-step Explanation: The triangle LMN has been given such that two sides m equals 5.9 and n equals 8.7. Also line l is not given but angle L equals 163. We shall apply the cosine rule to calculate for side l as the given dimensions satisfy the requirements to apply that formulae. The cosine rule states that;

    c^2 = a^ + b^2 - 2abCosC

    Using the dimensions given, the formulae can be re-written as,

    l^2 = m^2 + n^2 - (2mnCosL)

    l^2 = 5.9^2 + 8.7^2 - (2{5.9 x 8.7} CosL)

    l^2 = 34.81 + 75.69 - 2 (51.33) x - 0.9563

    l^2 = 110.5 + 98.1738

    l^2 = 208.6738

    Add the square root sign to both sides of the equation

    l = 14.4455

    Approximately to the nearest tenth of a centimeter, l equals 14.5 centimeters
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