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24 April, 19:17

Triangle fgh is inscribed in circle o the length of radius oh is 6 and fh is congruent to og. what is the area of the sector formed by angle foh

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  1. 24 April, 19:33
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    Given:

    Triangle fgh is inscribed in circle o

    oh = 6 = radius of the circle

    ∵ fh is congruent to og

    ∴ fh = og = radius og the circle = 6

    ∵ of = radius of the circle = 6

    ∴ oh = fh = of = radius of the circle = 6

    ∴ Δ foh is Equilateral Triangle

    ∴∠ foh = 60° ⇒⇒⇒ property of the equilateral Triangle

    ∵ total area of the circle = π r² and total central angle of the circle = 360°

    ∴ Area of sector foh = (60°/360°) * π r²

    ∴ Area of sector foh = (60°/360°) * π * 6² ≈ 18.85

    The answer is:

    the area of the sector formed by angle foh = 18.85
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