How do I evaluate the six trigonomic functions of a right triangle with the hypotenuse of 25 and and the adjacent of 24

First find the dimensions of the triangle by using the Pythagorean's theorem.

a^2+b^2=c^2

*c is always the hypotenuse

24^2+b^2=25^2

576+b^2=625

625-576=b^2

49=b^2

Square root of 49 = + or - 7b=+-7

*negative numbers are not often used in length for sides therefore we will be using the positive number.

Tan=opposite/adjacent = 7/24

Sin=opp/hypotenuse = 7/25

Cos = adjacent/hypo = 24/25

Cot=Tan^-1 (inverse) = 24/7

Csc = Sin^-1 = 25/7

Sec = Cos^-1 = 25/24