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1 September, 12:51

Select the solution for the system of linear equations y=3x+4 and y=x+2

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Answers (2)
  1. 1 September, 13:02
    0
    ( - 1, 1)

    Step-by-step explanation:

    Given the 2 equations

    y = 3x + 4 → (1)

    y = x + 2 → (2)

    Substitute y = 3x + 4 into (2)

    3x + 4 = x + 2 (subtract x from both sides)

    2x + 4 = 2 (subtract 4 from both sides)

    2x = - 2 (divide both sides by 2)

    x = - 1

    Substitute x = - 1 into either of the 2 equations and evaluate for y

    Substituting x = - 1 into (2)

    y = - 1 + 2 = 1

    Solution is ( - 1, 1)
  2. 1 September, 13:20
    0
    the solutions are

    y = 1; x = - 1

    Step-by-step explanation:

    Given two equations

    3x + 4 = y ... (1)

    x + 2 = y ... (2)

    From equation (2), we make x subject of formula to form a new equation (3) by subtracting 2 from both sides of the equation

    x + 2 - 2 = y - 2

    x = y - 2 ... (3)

    Now we substitute the value of x in equation (3) into equation (1)

    3x + 4 = y

    3 (y - 2) + 4 = y

    3y - 6 + 4 = y

    3y - 2 = y

    Add 2 to both sides of the equation

    3y - 2 + 2 = y + 2

    3y = y + 2

    Subtract your from both sides

    3y - y = y + 2 - y

    2y = 2

    Divide both sides by 2

    2y/2 = 2/2

    y = 1

    Now we substitute the new value of y = 1 into equation (2)

    x + 2 = y

    x + 2 = 1

    x + 2 - 2 = 1 - 2

    x = - 1
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