The equation of a parabola is given. y=-112x2-2x-1 What are the coordinates of the focus of the parabol

Using a graphing calculator, u can plot y=-112x2-2x-1

it is a concave parabola with focus at approx. (-0.0089, - 0.9933)

IF the equation is y=-1/12x^2-2x-1

then - 12y=x^2+24x+12

-12y+132=x^2+24x+144

-12 (y-11) = (x+12) ^2

so the vertex of the parabola is at (-12, 11)

semi axis length=12/4=3

the focus is at (-12, 11-3) = (-12, 8)