Find three solutions of the equation (x^2-9) (x^3-8) = 0

(x^2-9) (x^3-8) = 0

as you can see that (x^2-9) is in the form of a^2 - b^2 which equals (a+b) (a-b)

x^2 - 9

= (x) ^2 - (3) ^2

= (x+3) (x-3)

now, the equation becomes

(x+3) (x-3) (x^3-8) = 0

(x+3) = 0

x = - 3

(x-3) = 0

x = 3

x^3 - 8 = 0

x^3 = 8

x = cube rt. 8

= 2

so, the three solutions are - 3, 3 and 2.