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8 July, 06:35

In triangle abc, ab=90 in, bc=80 in, and angle b measures 50°. what is the approximate perimeter of the triangle?

a) 242.4 in.

b) 265.3 in.

c) 308.3 in.

d) 324.1 in.

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Answers (1)
  1. 8 July, 06:37
    0
    You need to use the Law of Cosines:

    AC² = AB² + BC² - 2·AB·BC·cos (b)

    Therefore, you get:

    AC = √ (90² + 80² - 2·90·80·cos (50)

    =√5243.86

    = 72.4 in

    Now you can sum up all the sides in order to find the perimeter:

    AB + BC + AC = 90 + 80 + 72.4 = 242.4 in

    The correct answer is A) 242.4 in
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