Write and solve an inequality to find the values of x for which the perimeter of the rectangle is less than 120.

A rectangle has a width of x and a length of x plus 4.

Inequality : 4x+8 < 120

x<28

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Perimeter of a rectangle (P) = 2 length + 2 width

Where:

Width = x

Length = x+4

Replacing with the values given

P = 2 (x+4) + 2x

P = 2x+8+2x

P=4x+8

Since the perimeter of the rectangle must be less than 120:

4x+8 < 120

Solving for x

4x<120-8

4x<112

x<112/4

x<28

Feel free to ask for more if needed or if you did not understand something.