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23 February, 21:11

The radius of a sphere is increasing at a constant of 2 cm/sec at the instant when the volume of the sphere is increasing at 32pi cm^3. sec, What is the surface area of the sphere?

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  1. 23 February, 21:21
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    The formula for the volume (v) of sphere is,

    v = 4πr³ / 3

    The derivative is,

    dv/dt = 4πr² (dr/dt)

    It is given that the radius changes at a rate of 2 cm/sec which means that dr/dt is 2. dv/dt is also given to be 32π cm³/sec. Substituting these to the given,

    32π = 4πr² x 2

    The value of 4πr² which is the surface area is equal to 16π. Thus, the surface area of the sphere is 16π cm².
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