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29 August, 03:04

What is the area of the triangle enclosed by the lines y=0, x=8 and y = x?

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  1. 29 August, 03:28
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    Since we have a horizontal line, y=0 on the x-axis, a vertical line at x=8, and a 45 degree angle line from y=x.

    So you essentially have a right triangle with a base that is 8 units wide, and a side that is 8 units high.

    Since the area is bh/2, A=8*8/2=32u^2
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