A mixture of soil is 57% clay, 39% silt, and 4% sand, measured by weight. If you had 3000 pounds of this soil, how many pounds of clay, silt, and sand would you have?

Question

Freddy Hunt

Mathematics

22 September, 06:39

A mixture of soil is 57% clay, 39% silt, and 4% sand, measured by weight. If you had 3000 pounds of this soil, how many pounds of clay, silt, and sand would you have?

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Answers (1)

Know the Answer?

Carlen · Answer 1

To find the answer all you have to do is multiply each of the percentages by 3000.

57% clay

.57 * 3000 = 1,710 lb

39% silt

.39 * 3000 = 1,170 lb

4% sand

.04 * 3000 = 120 lb

Check your answer by adding the weights together. They should add up to 3000.

1710 + 1170 + 120 = 3000

It checks!