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4 January, 01:41

Find the equation of the quadratic function with zeros - 1 and 1 and a vertex at (0,-4)

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  1. 4 January, 02:02
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    The equation is f (x) = 4x^2 - 4.

    You can find this by using an equation with parenthesis that equal each of the zeros.

    f (x) = (x - 1) (x + 1)

    Now, this equation will not give us the vertex that we're looking for. So, we must add a constant being multiplied to the front of it.

    f (x) = c (x - 1) (x + 1)

    Now we can find the constant by putting our vertex into the equation and solving.

    f (x) = c (x - 1) (x + 1)

    -4 = c (0 - 1) (0 + 1)

    -4 = c (-1) (1)

    -4 = - 1c

    c = 4

    Now we put the c into the original equation and solve for standard form.

    f (x) = 4 (x - 1) (x + 1)

    f (x) = 4 (x^2 - 1)

    f (x) = 4x^2 - 4
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