23 April, 13:34
For what value of x is sin x = cos 19º, where 0°< x < 90°?
23 April, 15:14
The cosine of an angle is equal to the sine of its complement:
cos (19°) = sin (90° - 19°) = sin (71°)
Comparing to the given expression, we see that x = 71°.
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» For what value of x is sin x = cos 19º, where 0°< x < 90°?