Second derivative test for:

y = e^x (x^2 - 7x + 13)

Question

Alexis Nolan

Mathematics

5 October, 09:25

Second derivative test for:

y = e^x (x^2 - 7x + 13)

+1

Answers (1)

Know the Answer?

Gillian Irwin · Answer 1

Hello

y = e^x (x^2 - 7x + 13)

y' = (e^x) ' (x^2 - 7x + 13) + e^x (x^2 - 7x + 13) '

y' = e^x (x^2 - 7x + 13) + e^x (2x-7)

y" = e^x (x^2 - 7x + 13) + e^x (2)

y"=e^x (x^2 - 7x + 15)

Second derivative test for:y = e^x (x^2 - 7x + 13)

Second derivative test for:

y = e^x (x^2 - 7x + 13)