The cost equation for a company to install x square feet of brick pathway is C = 234 + 14x, and the cost equation for a second company to install x square feet of

brick pathway is C = 23x. What is the area of the path that could be built by either company for the same cost? How much would it cost?

What is the area of the path that could be built by either company for the same cost? Select the correct choice below and fill in the answer box within your choice.

square feet.

O A The area of the path that could be built by either company for the same cost is

(Type a whole number.)

OB. The costs are never equal

How much would it cost? Select the correct choice below and fill in the answer box within your choice

O A It would cost $

(Type a whole number.)

OB. The costs are never equal

Question

Steve Branch

Mathematics

14 May, 10:48

The cost equation for a company to install x square feet of brick pathway is C = 234 + 14x, and the cost equation for a second company to install x square feet of

brick pathway is C = 23x. What is the area of the path that could be built by either company for the same cost? How much would it cost?

What is the area of the path that could be built by either company for the same cost? Select the correct choice below and fill in the answer box within your choice.

square feet.

O A The area of the path that could be built by either company for the same cost is

(Type a whole number.)

OB. The costs are never equal

How much would it cost? Select the correct choice below and fill in the answer box within your choice

O A It would cost $

(Type a whole number.)

OB. The costs are never equal

+2

Answers (1)

Know the Answer?

Rogelio Lyons · Answer 1

Step-by-step explanation:

Let A be first company

Install x square feet of brick pathway cost

C₁ = 234 + 14x

And company B to install x feet of brick charge

C₂ = 23x

If we make C₁ = C₂ we will find the area in which the cost will be the same for the two companies

Therefore

C₁ = C₂

234 + 14x = 23x

- 23x + 14x = - 234

-9x = - 234

x = 234/9

x = 26 ft² is the area that could be installed by either company at the same cost

How much would it cost

C₁ = 234 + 14x C₂ = 23*x

C₁ = 234 + 364 C₂ = 23*26

C₁ = 598 monetary units C₂ = 598 monetary units