How do you factor the trinomial 3x^2+18x-21?

(3) (x+7) (x-1)

Step-by-step explanation:

3x^2+18x-21

Let's start by taking 3 out of the equation.

3 (x^2+6x-7)

Now, when we factor, we need to find two numbers that add up to 6 and multiply to - 7.

The numbers would be 7 and - 1.

So the factored form of this would be:

(3) (x+7) (x-1)