The product of two numbers is 60. If half of their sum is 16, what are the two numbers?

Step-by-step explanation:

Let the two numbers be x& y

Product of the two number is

xy=60 ... i

Half of the Sum of the two number

x+y/2=16 ... ii

Solve simultaneously

When we cross multiply,

Equation 2 will be

X+y=32

make x subject of formulate

x=32-y

Substitute for x in equation 1

y (32-y) = 60

32y-y^2=60

Rearrange we get

Y^2-32y+60

Factorise

y^2-30y-2y+60

(y^2-30y) - (2y+60)

y (y-30) - 2 (y-30)

(y-30) (y-2) = 0

y=30 and y=2

To get x

When y=30

x=32-y

x=32-30

x=2

When y=2

X=32-y

x=32-2

x=30

Therefore y=30,2 and x=30,2

30 and 2

Step-by-step explanation:

I'm not so sure about this but when you add 30 + 2 that equals 32 and then if you divide by 2 you get 16 (and the you when times 30 x 2 you get 60