The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer the driver applies the brakes.

How many seconds after the driver applies the brakes does the car come to a stop

Question

Jeramiah Allen

Mathematics

31 March, 21:02

The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer the driver applies the brakes.

How many seconds after the driver applies the brakes does the car come to a stop

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Answers (1)

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Arjun Bell · Answer 1

s = 60t - 3t^2

v = ds/dt = 60 - 6t

when it comes to rest, v = 0,

so t = 10 sec

now distance travelled = time taken x average velocity

= 10 x (60 + 0) / 2

= 300 ft

The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer the driver applies the brakes.How many seconds after the driver applies the brakes does the car come to a stop

The driver of a car traveling at 54ft/sec suddenly applies the brakes. The position of the car is s=54t-3t^2, t seconds afyer the driver applies the brakes.

How many seconds after the driver applies the brakes does the car come to a stop