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8 February, 02:53

Find the equation in slope-intercept form that describes a line through (4, 2) with slope 12

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Answers (2)
  1. 8 February, 02:58
    0
    The equation in slope-intercept form is Y = 12X - 46.

    Step-by-step explanation:

    Step 1:

    Using the formula.

    Y - Y1 = m (X - X1)

    Step 2:

    Given dа ta:

    (X1, Y1) = (4, 2)

    m = 12.

    Step 3:

    Substitute the X1 as 4, Y1 as 2 and m as 12 in the given equation.

    [Y - Y1 = m (X - X1).]

    Y - 2 = 12 (X - 4)

    Step 4:

    Multiply 12 with (X - 4).

    Y - 2 = 12X - 48

    Keep 'Y' in LHS and move - 2 to RHS

    Y = 12X - 48 + 2

    Y = 12X - 46.

    Hence Proved.
  2. 8 February, 02:59
    0
    The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x - 46

    Step-by-step explanation:

    We need to find the slope-intercept form of a line that passes through (4,2) and have slope of 12.

    The general form of slope-intercept form is: y = mx + b

    where m is the slope and b is the y-intercept.

    We are given slope m = 12

    We need to find y-intercept.

    Using the formula y = mx + b

    and putting values y=2, x = 4 and m = 12, and finding b

    y = mx + b

    2 = 12 (4) + b

    2 = 48+b

    => b = 2-48

    b = - 46

    So, value of b is b = - 46

    The equation in slope-intercept form will be:

    m = 12 and b = - 46

    y = mx + b

    y = 12x - 46

    The equation in slope-intercept form that describes a line through (4, 2) with slope 12 will be y = 12x - 46
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