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Darwin Hodges
Mathematics
17 June, 17:45
2x - 6 ≥ 6 (x - 2) + 8
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Aniya Brewer
17 June, 17:57
0
2x - 6 ≥ 6 (x - 2) + 8
2x - 6 ≥ 6x - 12 + 8
2x - 6 ≥ 6x - 4
-6 - 6
2x ≥ 6x - 10
-6x - 6x
-4x ≥ - 10
x < 2/5
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Tatum George
17 June, 18:09
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2x - 6 > 6 (x - 2) + 8
use the distrubutive property
2x - 6 > 6x - 12 + 8
combine like terms
2x - 6 > 6x - 4
get "x" on one side by subtracting 6x from both sides
-4x - 6 > - 4
add 6 to both sides so that you have x on one and actual numbers on the other
-4x > 2
divide both sides by - 4, and don't forget to flip the sign because you are dividing by a negative!
x < - 0.5 or x < - 1/2
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