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30 December, 16:54

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

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  1. 30 December, 17:02
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    Answer=25%

    14 red marbles

    12 yellow marbles

    26 total marbles

    To solve this, we need to first find out the probability of the individual events ...

    The odds of selecting a red marble is 14 out of 26 total marbles: 14/26

    The odds of selecting a yellow marble after the first marble was NOT replaced is 12 out of 25. (25 since the first marble wasn't replaced: 26-1=25) 12/25

    Now lets multiple both probabilities together to solve for the chance of both happening consecutively ...

    14/26*12/25 = 168/650=84/325

    84/325 = 0.25846153846 = 25%
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