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27 February, 13:18

How do I solve 12=3 (2x-10) + 6

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Answers (2)
  1. 27 February, 13:45
    0
    Hello.

    1. switch sides

    3 (2x-10) + 6=12

    2. subtract 6 from both sides

    3 (2x-10) + 6-6=12-6

    3. simplfy

    3 (2x-10) = 6

    4. divide both sides by 3

    3 (2x-10) / 3=6/3

    5. simpfly

    2x-10=2

    6. add 10 to both sides

    2x-10+10=2+10

    7 simpfly

    2x=12

    Answer=6

    have a nice day
  2. 27 February, 13:46
    0
    Subtract 6 from both sides and you get 6=3 (2x-10)

    Divide both sides by 3 and you get 6/ 3 =2x-10 and 6/3=2 so 2=2x-10

    then add 10 to both sides 2+10=2x and you get 12=2x divide by 2

    x=6 then check your answer and you get 12=12
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