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1 January, 22:33

The condition proves that triangle ABC and triangle EFG are congruent by the SAS criterion. If AB does not equal EF the criterion for congruency is violated. In this situation angle C angle G

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  1. 1 January, 22:36
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    If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G are not equal:

    angle C ≠ angle G
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