Weight A weighs 50 pounds. weight B weighs 100 pounds. if A is placed 6 feet from the pivot, how far must B be placed from the pivot in order for the bar to achieve balance?

Question

Alonzo Delacruz

Mathematics

8 December, 07:57

Weight A weighs 50 pounds. weight B weighs 100 pounds. if A is placed 6 feet from the pivot, how far must B be placed from the pivot in order for the bar to achieve balance?

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Answers (1)

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Twiggy · Answer 1

To achieve balance, the momentum on both sides must be equal so that it cancels out. Momentum is simply the product of mass and distance, therefore:

50 pounds * 6 ft = 100 pounds * X

X = 3 ft

Hence B must be placed 3 ft from the pivot.