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12 February, 00:15

Use the discriminant of the following quadratic equation to state the number and type of solutions. 3x^ (2) + 4x-5=3x+2

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  1. 12 February, 00:39
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    3x^ (2) + 4x-3x-5-2=0

    3x^ (2) + x-7=0

    Discriminat = b^ (2) - 4ac = 1^ (2) - 4 (3) (-7) = 1-12 (-7) = 1+84=85

    The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
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