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15 July, 05:06

Determine the function's value when x = - 1.

g (x) = x3 + 6x2 + 12x + 8

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  1. 15 July, 05:27
    0
    g (-1) = 1

    Step-by-step explanation:

    Using " ^ " to denote exponentiation, we get:

    g (x) = x^3 + 6x^2 + 12x + 8

    Substituting - 1 for x, we get:

    g (-1) = (-1) ^3 + 6 (-1) ^2 + 12 (-1) + 8, or

    g (-1) = - 1 + 6 - 12 + 8, or

    g (-1) = 1
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