The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 192 feet, what is the area of the garden in square feet?

The area of the garden is 2332 sq feet.

Step-by-step explanation:

Step 1:

Let us assume L be the width and L+8 length of the rectangular garden and also P be perimeter.

Step 2:

We got the equation from the given data.

P = 2. (2L + 8) = 4L + 16 = 192.

Divide by four on both sides of equation to yield.

(4L + 16) / 4 = 192/4

L + 4 = 48

L = 44

Step 3:

Area is length time's width for a rectangle.

A = L (L+8)

Step 4:

Substituting L=44 and L=53 into A yields

A = (44). (53) = 2332

Area = 2332 Square Feet.

Answer:The sides of the garden are x and x + 9

The perimeter of a rectangle is 2x + 2y (where x is the width and y is the length)

So your equation is:

2x + 2 (x+9) = 194

Distribute the 2s:

2x + 2x + 18 = 194

Simplify:

4x + 18 = 194

Combine like terms:

4x = 176

Solve for x:

x = 44

So the sides are 44 and 53

Area = xy so multiply to get your answer.