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26 March, 05:40

The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 192 feet, what is the area of the garden in square feet?

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Answers (2)
  1. 26 March, 05:49
    0
    The area of the garden is 2332 sq feet.

    Step-by-step explanation:

    Step 1:

    Let us assume L be the width and L+8 length of the rectangular garden and also P be perimeter.

    Step 2:

    We got the equation from the given data.

    P = 2. (2L + 8) = 4L + 16 = 192.

    Divide by four on both sides of equation to yield.

    (4L + 16) / 4 = 192/4

    L + 4 = 48

    L = 44

    Step 3:

    Area is length time's width for a rectangle.

    A = L (L+8)

    Step 4:

    Substituting L=44 and L=53 into A yields

    A = (44). (53) = 2332

    Area = 2332 Square Feet.
  2. 26 March, 06:02
    0
    Answer:The sides of the garden are x and x + 9

    The perimeter of a rectangle is 2x + 2y (where x is the width and y is the length)

    So your equation is:

    2x + 2 (x+9) = 194

    Distribute the 2s:

    2x + 2x + 18 = 194

    Simplify:

    4x + 18 = 194

    Combine like terms:

    4x = 176

    Solve for x:

    x = 44

    So the sides are 44 and 53

    Area = xy so multiply to get your answer.
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