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Brittany Douglas
Mathematics
16 November, 22:23
Solve the triangle B=71 degrees, b=15, c=8
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Wade Charles
16 November, 22:25
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SinC/8=sin71/15
sinC=8sin71/15
C=arcsin (8sin71/15) ≈30.28°
A=180-71-arcsin (8sin71/15) ≈78.72
a/sin78.72=15/sin71
a=15sin78.72/sin71≈15.56
So the angles and their opposite side lengths are:
A=78.72°, B=71, C=30.28°
a≈15.56, b=15, c=8
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