An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it falls is represented by the equation S (t) = - 16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air?

Question

Dropout

Mathematics

17 February, 22:04

An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the ground as it falls is represented by the equation S (t) = - 16t2 + 25, where t is the number of seconds. For which interval of time is the acorn moving through the air?

+3

Answers (1)

Know the Answer?

Rose Daniel · Answer 1

The equation is the initial distance of the acorn at time t. So in order to find the time for the acorn to reach the ground, we will just equate the equation above to zero and find t. We are going to get the positive value since there is no such thing as negative time. So for the acorn to reach the ground, it would take 1.25 seconds.