Perform the following application. Use 3.14 for and round to the nearest tenth. A culvert has a circumference of 280 cm. You wish to seal off both of its ends. What is the culvert's radius? cm. How much material will you need? sq. cm.

Question

Lorena Craig

Mathematics

28 January, 03:59

Perform the following application. Use 3.14 for and round to the nearest tenth. A culvert has a circumference of 280 cm. You wish to seal off both of its ends. What is the culvert's radius? cm. How much material will you need? sq. cm.

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Huynh · Answer 1

Culvert is a tunnel, therefore we can use the volume and area formula of a cylinder.

Circumference is given such as 280 cm and the circumference formula of a circle is C = 2*pi*r

Solving for the radius, we have:

280 = 2*3.14*r

r = 280/2*3.14

r = 44.59 cm

Area of one end:

Area = pi*r²

Area = 3.14 * 44.59²

Area = 6,243.2 cm²

The total area is times two of area since there were two ends in the culvert.

Total area = 6243.2 * 2

Total area = 12,486.32 cm²