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3 March, 07:52

Expand the following: 1/3 (6/5x-3)

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  1. 3 March, 07:57
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    x in (-oo:+oo)

    (1/3) * ((6/5) * x-3) = 0

    1/3 * (6/5*x-3) = 0

    (1/3)

    1/3 = 0

    x belongs to the empty set

    (6/5*x-3)

    6/5*x-3 = 0 / / + 3

    6/5*x = 3 / / : 6/5

    x = 3/6/5

    x = 5/2

    x = 5/2
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