Find f. f ''' (x) = cos (x), f (0) = 4, f ' (0) = 2, f '' (0) = 6

Given that every integration has constant C, and is solved by the 0 conditions stated in the problem;

f''' (x) = Cos (x)

f'' (x) = sin (x) + 6 after f'' (0) = 6

f' (x) = - cos (x) + 6x + 2 after f' (0) = 2

f (x) = - sin (x) + 3x^2 + 2x + 4 after f (0) = 4