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19 March, 20:30

Find the x-intercept (s) and the coordinates of the vertex for the parabola

=y+x^2-8x+12

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  1. 19 March, 20:49
    0
    The factors of the expression are:

    y = (x - 2) (x - 6)

    The x-intercepts are found by putting y = 0.

    Therefore the x-intercepts are at (2, 0) and (6, 0).

    The x value of the vertex is (2 + 6) / 2 = 4.

    f (4) = 16 - 32 + 12 = - 4.

    The coordinates of the vertex are (4, - 4).
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