Find the minimum value of C=x+3y

c

Step-by-step explanation:

2x + 3y > 6 (1)

3x - 2y = 9 (2)

x + 5y = 20 (3)

From (1) and (2), we have:

(2x + 3y) - (3x - 2y) > 6 - 9

5y - x > - 3 (4)

From (3) and (4), we have:

(x + 5y) - (5y - x) > 20 - (-3)

2x > 23

x > 12,5 (5)

From (3) and (5), we have:

x + 5y = 20 ⇔ 12,5 + 5y > 20

5y > 7,5

y > 1,5

So: C = 4x + 3y > 12,5 * 4 + 1,5 * 3 = 50 + 4,5 = 54,5

Conclusion: C > 54,5