In the lab, Leila has two solutions that contain alcohol and is mixing them with each other. Solution A is alcohol and Solution B is alcohol. She uses milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a alcohol solution?

300ml

Step-by-step explanation:

As values are missing in your question, the complete question is:

In the lab, Leila has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solution B is 20% alcohol. She uses 400 milliliters of Solution A. How many milliliters of Solution B does she use, if the resulting mixture is a 12% alcohol solution?

Considering x=ml of 20% solution B

Therefore, 400+x=ml of resulting 12% solution

Solution A alcohol + solution B alcohol = Alcohol solution

6% (400) + 20%x = 12% (400+x) - > (converting percentage into decimal)

.06*400+.2x=.12 (400+x)

24+.2x=48+.12x

.08x=24

x=24/.08=300 ml

she used 300 milliliters of 20%Solution B in resulting mixture.