Solving Exponential Equations (lacking a common base)

(0.52) ^q=4

Question

Ranger

Mathematics

8 June, 09:05

Solving Exponential Equations (lacking a common base)

(0.52) ^q=4

+5

Answers (2)

Know the Answer?

Kayden Wilkins · Answer 1

q = log4 / log0.53

q = - 2.189

Step-by-step explanation:

(0.53) ^q = 4

Taking log of both sides!

q log 0.53 = log 4

q = log 4 / log 0.53

q = 0.602 / - 0.275

q = - 2.189

This can be checked to confirm correctness.

Substituting q = - 2.189

(0.53) ^ - 2.189 = 1 / 0.249

= 4.01 Proved!

(Note that the "1" is because of the negative sign)

Rodney Caldwell · Answer 2

q = - 2.12

Step-by-step explanation:

lg both sides

lg (0.52^q) = lg4

qlg0.52 = lg4

q = lg4/lg0.52

q = - 2.12

Solving Exponential Equations (lacking a common base)(0.52) ^q=4

Solving Exponential Equations (lacking a common base)

(0.52) ^q=4