Solve. 1. - 3 (n+1) = 3; 2. 2 (c-12) = 0; 3. 38=-6t-4;

Question

Panther

Mathematics

3 January, 16:20

Solve. 1. - 3 (n+1) = 3; 2. 2 (c-12) = 0; 3. 38=-6t-4;

+3

Answers (2)

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Laney Montgomery · Answer 1

1.-3n-3=3 2.2c-24 = 0 3.42=-6t

-3n=6 2c=24 42/-6=t

n=6/-3 c=12 - 7=t

n=-2

Pablo Hodge · Answer 2

1. - 3 (n + 1) = 3.

-3n + - 3 = 3.

-3n + - 3 + 3 = 3 + 3.

-3n = 6.

-3n/-3 = 6/-3.

n = - 2.

2. 2 (c - 12) = 0.

2c - 24 = 0.

2c - 24 + 24 = 0 + 24.

2c = 24.

2c/2 = 24/2.

c = 12.

3. 38 = - 6t - 4.

38 + 4 = - 6t - 4 + 4.

42 = - 6t.

42/-6 = - 6t/-6.

-7 = t.